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142012111303 = 208073682511
BaseRepresentation
bin1000010001000010010…
…1001101100111000111
3111120120001211201120001
42010100211031213013
54311320100030203
6145123420222131
713155123013006
oct2042045154707
9446501751501
10142012111303
1155255153147
122363369a947
13105126b9bba
146c3295ac3d
153a626c791d
hex211094d9c7

142012111303 has 4 divisors (see below), whose sum is σ = 142013001888. Its totient is φ = 142011220720.

The previous prime is 142012111291. The next prime is 142012111321. The reversal of 142012111303 is 303111210241.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 142012111303 - 29 = 142012110791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142012111403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133183 + ... + 549328.

It is an arithmetic number, because the mean of its divisors is an integer number (35503250472).

Almost surely, 2142012111303 is an apocalyptic number.

142012111303 is a deficient number, since it is larger than the sum of its proper divisors (890585).

142012111303 is an equidigital number, since it uses as much as digits as its factorization.

142012111303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 890584.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 142012111303 its reverse (303111210241), we get a palindrome (445123321544).

The spelling of 142012111303 in words is "one hundred forty-two billion, twelve million, one hundred eleven thousand, three hundred three".

Divisors: 1 208073 682511 142012111303