14201211210241 has 4 divisors (see below), whose sum is σ = 15492230411184. Its totient is φ = 12910192009300.

The previous prime is 14201211210227. The next prime is 14201211210269.

14201211210241 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14201211210241 - 2¹⁵ = 14201211177473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14201211210271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 645509600455 + ... + 645509600476.

It is an arithmetic number, because the mean of its divisors is an integer number (3873057602796).

Almost surely, 2^{14201211210241} is an apocalyptic number.

14201211210241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14201211210241 is a deficient number, since it is larger than the sum of its proper divisors (1291019200943).

14201211210241 is a wasteful number, since it uses less digits than its factorization.

14201211210241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1291019200942.

The product of its (nonzero) digits is 256, while the sum is 22.

It can be divided in two parts, 1420121 and 1210241, that added together give a palindrome (2630362).

The spelling of 14201211210241 in words is "fourteen trillion, two hundred one billion, two hundred eleven million, two hundred ten thousand, two hundred forty-one".