Base | Representation |
---|---|
bin | 1000010001000010100… |
… | …0101001101100010001 |
3 | 111120120010112112010002 |
4 | 2010100220221230101 |
5 | 4311320312402003 |
6 | 145123451415345 |
7 | 13155133456103 |
oct | 2042050515421 |
9 | 446503475102 |
10 | 142013012753 |
11 | 55255709447 |
12 | 23633a54555 |
13 | 105129442c1 |
14 | 6c32b13573 |
15 | 3a62804a88 |
hex | 2110a29b11 |
142013012753 has 2 divisors, whose sum is σ = 142013012754. Its totient is φ = 142013012752.
The previous prime is 142013012741. The next prime is 142013012759. The reversal of 142013012753 is 357210310241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115649645329 + 26363367424 = 340073^2 + 162368^2 .
It is a cyclic number.
It is not a de Polignac number, because 142013012753 - 28 = 142013012497 is a prime.
It is not a weakly prime, because it can be changed into another prime (142013012759) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71006506376 + 71006506377.
It is an arithmetic number, because the mean of its divisors is an integer number (71006506377).
Almost surely, 2142013012753 is an apocalyptic number.
It is an amenable number.
142013012753 is a deficient number, since it is larger than the sum of its proper divisors (1).
142013012753 is an equidigital number, since it uses as much as digits as its factorization.
142013012753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 142013012753 its reverse (357210310241), we get a palindrome (499223322994).
The spelling of 142013012753 in words is "one hundred forty-two billion, thirteen million, twelve thousand, seven hundred fifty-three".
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