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142013198183 is a prime number
BaseRepresentation
bin1000010001000010100…
…1010110111101100111
3111120120010212221110212
42010100221112331213
54311320334320213
6145123455410035
713155135160523
oct2042051267547
9446503787425
10142013198183
115525582579a
1223633b2391b
13105129aa81c
146c32b60d83
153a6283e9a8
hex2110a56f67

142013198183 has 2 divisors, whose sum is σ = 142013198184. Its totient is φ = 142013198182.

The previous prime is 142013198137. The next prime is 142013198203. The reversal of 142013198183 is 381891310241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142013198183 - 214 = 142013181799 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 142013198183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142013198123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71006599091 + 71006599092.

It is an arithmetic number, because the mean of its divisors is an integer number (71006599092).

Almost surely, 2142013198183 is an apocalyptic number.

142013198183 is a deficient number, since it is larger than the sum of its proper divisors (1).

142013198183 is an equidigital number, since it uses as much as digits as its factorization.

142013198183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 41.

The spelling of 142013198183 in words is "one hundred forty-two billion, thirteen million, one hundred ninety-eight thousand, one hundred eighty-three".