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142013443217957 is a prime number
BaseRepresentation
bin100000010010100100010100…
…110101100001101000100101
3200121211100112000212121202122
4200102210110311201220211
5122103222012430433312
61222012024122515325
741625063340203323
oct4022442465415045
9617740460777678
10142013443217957
1141282621460713
1213b171a6965b45
136131a6c10a4bc
14270d6b731ad13
1511641677b9b72
hex812914d61a25

142013443217957 has 2 divisors, whose sum is σ = 142013443217958. Its totient is φ = 142013443217956.

The previous prime is 142013443217897. The next prime is 142013443217963. The reversal of 142013443217957 is 759712344310241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116558128771681 + 25455314446276 = 10796209^2 + 5045326^2 .

It is a cyclic number.

It is not a de Polignac number, because 142013443217957 - 212 = 142013443213861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142013443217899 and 142013443217908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142013443217557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71006721608978 + 71006721608979.

It is an arithmetic number, because the mean of its divisors is an integer number (71006721608979).

Almost surely, 2142013443217957 is an apocalyptic number.

It is an amenable number.

142013443217957 is a deficient number, since it is larger than the sum of its proper divisors (1).

142013443217957 is an equidigital number, since it uses as much as digits as its factorization.

142013443217957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 53.

The spelling of 142013443217957 in words is "one hundred forty-two trillion, thirteen billion, four hundred forty-three million, two hundred seventeen thousand, nine hundred fifty-seven".