Base | Representation |
---|---|
bin | 10100101010101010100… |
… | …101010111100011111010 |
3 | 12000202210020222112112112 |
4 | 110222222211113203322 |
5 | 141232032442131414 |
6 | 3004233103012322 |
7 | 204414623266325 |
oct | 24525245274372 |
9 | 5022706875475 |
10 | 1420201130234 |
11 | 4a8338571447 |
12 | 1ab2b259a0a2 |
13 | a3c02b73383 |
14 | 4ca494c97bc |
15 | 26e218a9d3e |
hex | 14aaa9578fa |
1420201130234 has 4 divisors (see below), whose sum is σ = 2130301695354. Its totient is φ = 710100565116.
The previous prime is 1420201130209. The next prime is 1420201130287. The reversal of 1420201130234 is 4320311020241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1272666015625 + 147535114609 = 1128125^2 + 384103^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 355050282557 + ... + 355050282560.
Almost surely, 21420201130234 is an apocalyptic number.
1420201130234 is a deficient number, since it is larger than the sum of its proper divisors (710100565120).
1420201130234 is an equidigital number, since it uses as much as digits as its factorization.
1420201130234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710100565119.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1420201130234 its reverse (4320311020241), we get a palindrome (5740512150475).
The spelling of 1420201130234 in words is "one trillion, four hundred twenty billion, two hundred one million, one hundred thirty thousand, two hundred thirty-four".
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