Base | Representation |
---|---|
bin | 1100111010101010101110… |
… | …1110100111101001011101 |
3 | 1212021200221210111001222112 |
4 | 3032222223232213221131 |
5 | 3330141241002134113 |
6 | 50112154541523405 |
7 | 2664030602512655 |
oct | 316525356475135 |
9 | 55250853431875 |
10 | 14202043005533 |
11 | 4586064037109 |
12 | 171454b573565 |
13 | 7c03295c7026 |
14 | 37154da01365 |
15 | 1996638cc5a8 |
hex | ceaabba7a5d |
14202043005533 has 4 divisors (see below), whose sum is σ = 14202068695548. Its totient is φ = 14202017315520.
The previous prime is 14202043005529. The next prime is 14202043005583. The reversal of 14202043005533 is 33550034020241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5212467984889 + 8989575020644 = 2283083^2 + 2998262^2 .
It is a cyclic number.
It is not a de Polignac number, because 14202043005533 - 22 = 14202043005529 is a prime.
It is a super-2 number, since 2×142020430055332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14202043005533.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14202043005583) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11997116 + ... + 13127637.
It is an arithmetic number, because the mean of its divisors is an integer number (3550517173887).
Almost surely, 214202043005533 is an apocalyptic number.
It is an amenable number.
14202043005533 is a deficient number, since it is larger than the sum of its proper divisors (25690015).
14202043005533 is an equidigital number, since it uses as much as digits as its factorization.
14202043005533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25690014.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 14202043005533 its reverse (33550034020241), we get a palindrome (47752077025774).
The spelling of 14202043005533 in words is "fourteen trillion, two hundred two billion, forty-three million, five thousand, five hundred thirty-three".
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