Base | Representation |
---|---|
bin | 10100101010101101000… |
… | …101000110110000110111 |
3 | 12000202220011202222012012 |
4 | 110222231011012300313 |
5 | 141232124202120341 |
6 | 3004241200314435 |
7 | 204415642231544 |
oct | 24525505066067 |
9 | 5022804688165 |
10 | 1420243004471 |
11 | 4a835a172155 |
12 | 1ab304612a1b |
13 | a3c0b745025 |
14 | 4ca50ca9bcb |
15 | 26e253cc0eb |
hex | 14aad146c37 |
1420243004471 has 2 divisors, whose sum is σ = 1420243004472. Its totient is φ = 1420243004470.
The previous prime is 1420243004443. The next prime is 1420243004489. The reversal of 1420243004471 is 1744003420241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1420243004471 is a prime.
It is a super-3 number, since 3×14202430044713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420243004491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710121502235 + 710121502236.
It is an arithmetic number, because the mean of its divisors is an integer number (710121502236).
Almost surely, 21420243004471 is an apocalyptic number.
1420243004471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420243004471 is an equidigital number, since it uses as much as digits as its factorization.
1420243004471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 32.
The spelling of 1420243004471 in words is "one trillion, four hundred twenty billion, two hundred forty-three million, four thousand, four hundred seventy-one".
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