Base | Representation |
---|---|
bin | 11010011101001000… |
… | …10001011111010001 |
3 | 1100122211111212020202 |
4 | 31032210101133101 |
5 | 213041434033203 |
6 | 10305204144545 |
7 | 1011651536042 |
oct | 151644213721 |
9 | 40584455222 |
10 | 14203033553 |
11 | 6029273365 |
12 | 2904698155 |
13 | 14546b8b87 |
14 | 98a4488c9 |
15 | 581d8b388 |
hex | 34e9117d1 |
14203033553 has 2 divisors, whose sum is σ = 14203033554. Its totient is φ = 14203033552.
The previous prime is 14203033547. The next prime is 14203033561. The reversal of 14203033553 is 35533030241.
14203033553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10115732929 + 4087300624 = 100577^2 + 63932^2 .
It is a cyclic number.
It is not a de Polignac number, because 14203033553 - 218 = 14202771409 is a prime.
It is not a weakly prime, because it can be changed into another prime (14203033513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101516776 + 7101516777.
It is an arithmetic number, because the mean of its divisors is an integer number (7101516777).
Almost surely, 214203033553 is an apocalyptic number.
It is an amenable number.
14203033553 is a deficient number, since it is larger than the sum of its proper divisors (1).
14203033553 is an equidigital number, since it uses as much as digits as its factorization.
14203033553 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 29.
Adding to 14203033553 its reverse (35533030241), we get a palindrome (49736063794).
The spelling of 14203033553 in words is "fourteen billion, two hundred three million, thirty-three thousand, five hundred fifty-three".
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