Base | Representation |
---|---|
bin | 1100111010101110011100… |
… | …1101101101011001111001 |
3 | 1212021210112100102000112212 |
4 | 3032223213031231121321 |
5 | 3330200311444330241 |
6 | 50112441552344505 |
7 | 2664064411436561 |
oct | 316534715553171 |
9 | 55253470360485 |
10 | 14203041011321 |
11 | 4586526418688 |
12 | 1714789845135 |
13 | 7c04582b65b6 |
14 | 37160638dda1 |
15 | 1996c1317beb |
hex | ceae736d679 |
14203041011321 has 4 divisors (see below), whose sum is σ = 14505233373312. Its totient is φ = 13900848649332.
The previous prime is 14203041011287. The next prime is 14203041011363. The reversal of 14203041011321 is 12311014030241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14203041011321 - 210 = 14203041010297 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14203041016321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151096180925 + ... + 151096181018.
It is an arithmetic number, because the mean of its divisors is an integer number (3626308343328).
Almost surely, 214203041011321 is an apocalyptic number.
It is an amenable number.
14203041011321 is a deficient number, since it is larger than the sum of its proper divisors (302192361991).
14203041011321 is an equidigital number, since it uses as much as digits as its factorization.
14203041011321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302192361990.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14203041011321 its reverse (12311014030241), we get a palindrome (26514055041562).
The spelling of 14203041011321 in words is "fourteen trillion, two hundred three billion, forty-one million, eleven thousand, three hundred twenty-one".
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