Base | Representation |
---|---|
bin | 1100111010101110101110… |
… | …0001000101100110001011 |
3 | 1212021210201101020120211001 |
4 | 3032223223201011212023 |
5 | 3330200433434400021 |
6 | 50112453051515431 |
7 | 2664066246150331 |
oct | 316535341054613 |
9 | 55253641216731 |
10 | 14203113200011 |
11 | 458656314405a |
12 | 17147a9a58b77 |
13 | 7c046a2403b8 |
14 | 371611bc1b51 |
15 | 1996c7827091 |
hex | ceaeb84598b |
14203113200011 has 4 divisors (see below), whose sum is σ = 14210745181024. Its totient is φ = 14195481219000.
The previous prime is 14203113199991. The next prime is 14203113200021. The reversal of 14203113200011 is 11000231130241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14203113200011 - 27 = 14203113199883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14203113200021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3815987715 + ... + 3815991436.
It is an arithmetic number, because the mean of its divisors is an integer number (3552686295256).
Almost surely, 214203113200011 is an apocalyptic number.
14203113200011 is a deficient number, since it is larger than the sum of its proper divisors (7631981013).
14203113200011 is an equidigital number, since it uses as much as digits as its factorization.
14203113200011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7631981012.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 14203113200011 its reverse (11000231130241), we get a palindrome (25203344330252).
The spelling of 14203113200011 in words is "fourteen trillion, two hundred three billion, one hundred thirteen million, two hundred thousand, eleven".
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