142031233340131 has 8 divisors (see below), whose sum is σ = 142052736187584. Its totient is φ = 142009732075560.

The previous prime is 142031233340071. The next prime is 142031233340167. The reversal of 142031233340131 is 131043332130241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142031233340131 - 2¹⁷ = 142031233209059 is a prime.

It is a super-3 number, since 3×142031233340131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142031233340093 and 142031233340102.

It is not an unprimeable number, because it can be changed into a prime (142031233350131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185639136 + ... + 186402658.

It is an arithmetic number, because the mean of its divisors is an integer number (17756592023448).

Almost surely, 2^{142031233340131} is an apocalyptic number.

142031233340131 is a deficient number, since it is larger than the sum of its proper divisors (21502847453).

142031233340131 is a wasteful number, since it uses less digits than its factorization.

142031233340131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 791441.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 142031233340131 its reverse (131043332130241), we get a palindrome (273074565470372).

The spelling of 142031233340131 in words is "one hundred forty-two trillion, thirty-one billion, two hundred thirty-three million, three hundred forty thousand, one hundred thirty-one".