Search a number
-
+
1420314306347 is a prime number
BaseRepresentation
bin10100101010110001010…
…101000110011100101011
312000210002010221110222102
4110222301111012130223
5141232300430300342
63004252224444015
7204420466256666
oct24526125063453
95023063843872
101420314306347
114a8396442322
121ab32447960b
13a3c2044b2a1
144ca5a54a6dd
1526e2b7b3832
hex14ab154672b

1420314306347 has 2 divisors, whose sum is σ = 1420314306348. Its totient is φ = 1420314306346.

The previous prime is 1420314306343. The next prime is 1420314306349. The reversal of 1420314306347 is 7436034130241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1420314306347 - 22 = 1420314306343 is a prime.

Together with 1420314306349, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1420314306347.

It is not a weakly prime, because it can be changed into another prime (1420314306343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710157153173 + 710157153174.

It is an arithmetic number, because the mean of its divisors is an integer number (710157153174).

Almost surely, 21420314306347 is an apocalyptic number.

1420314306347 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420314306347 is an equidigital number, since it uses as much as digits as its factorization.

1420314306347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 38.

Adding to 1420314306347 its reverse (7436034130241), we get a palindrome (8856348436588).

The spelling of 1420314306347 in words is "one trillion, four hundred twenty billion, three hundred fourteen million, three hundred six thousand, three hundred forty-seven".