Base | Representation |
---|---|
bin | 11010011101001011… |
… | …10010100011100110 |
3 | 1100122212021001122021 |
4 | 31032211302203212 |
5 | 213042034244032 |
6 | 10305220453354 |
7 | 1011655113145 |
oct | 151645624346 |
9 | 40585231567 |
10 | 14203431142 |
11 | 602951504a |
12 | 290484a25a |
13 | 14547c7b34 |
14 | 98a50d75c |
15 | 581e19097 |
hex | 34e9728e6 |
14203431142 has 4 divisors (see below), whose sum is σ = 21305146716. Its totient is φ = 7101715570.
The previous prime is 14203431127. The next prime is 14203431163. The reversal of 14203431142 is 24113430241.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3550857784 + ... + 3550857787.
It is an arithmetic number, because the mean of its divisors is an integer number (5326286679).
Almost surely, 214203431142 is an apocalyptic number.
14203431142 is a deficient number, since it is larger than the sum of its proper divisors (7101715574).
14203431142 is an equidigital number, since it uses as much as digits as its factorization.
14203431142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7101715573.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14203431142 its reverse (24113430241), we get a palindrome (38316861383).
Subtracting 14203431142 from its reverse (24113430241), we obtain a palindrome (9909999099).
The spelling of 14203431142 in words is "fourteen billion, two hundred three million, four hundred thirty-one thousand, one hundred forty-two".
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