14203501332442 has 4 divisors (see below), whose sum is σ = 21305251998666. Its totient is φ = 7101750666220.

The previous prime is 14203501332413. The next prime is 14203501332451. The reversal of 14203501332442 is 24423310530241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13001800851601 + 1201700480841 = 3605801^2 + 1096221^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14203501332398 and 14203501332407.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3550875333109 + ... + 3550875333112.

Almost surely, 2^{14203501332442} is an apocalyptic number.

14203501332442 is a deficient number, since it is larger than the sum of its proper divisors (7101750666224).

14203501332442 is an equidigital number, since it uses as much as digits as its factorization.

14203501332442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7101750666223.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 14203501332442 its reverse (24423310530241), we get a palindrome (38626811862683).

The spelling of 14203501332442 in words is "fourteen trillion, two hundred three billion, five hundred one million, three hundred thirty-two thousand, four hundred forty-two".