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142035124769 is a prime number
BaseRepresentation
bin1000010001000111110…
…1000000001000100001
3111120121200010221002122
42010101331000020201
54311341442443034
6145130001354025
713155522432446
oct2042175001041
9446550127078
10142035124769
115526714153a
122363b338915
13105173b6b35
146c35a2b9cd
153a6472162e
hex2111f40221

142035124769 has 2 divisors, whose sum is σ = 142035124770. Its totient is φ = 142035124768.

The previous prime is 142035124753. The next prime is 142035124771. The reversal of 142035124769 is 967421530241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90608224144 + 51426900625 = 301012^2 + 226775^2 .

It is an emirp because it is prime and its reverse (967421530241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142035124769 - 24 = 142035124753 is a prime.

It is a super-2 number, since 2×1420351247692 (a number of 23 digits) contains 22 as substring.

Together with 142035124771, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142035154769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71017562384 + 71017562385.

It is an arithmetic number, because the mean of its divisors is an integer number (71017562385).

Almost surely, 2142035124769 is an apocalyptic number.

It is an amenable number.

142035124769 is a deficient number, since it is larger than the sum of its proper divisors (1).

142035124769 is an equidigital number, since it uses as much as digits as its factorization.

142035124769 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 44.

The spelling of 142035124769 in words is "one hundred forty-two billion, thirty-five million, one hundred twenty-four thousand, seven hundred sixty-nine".