Base | Representation |
---|---|
bin | 1100111010110000010100… |
… | …1100100111001110100001 |
3 | 1212021211211101221112122202 |
4 | 3032230011030213032201 |
5 | 3330202324233242403 |
6 | 50113003522142545 |
7 | 2664113030220533 |
oct | 316540514471641 |
9 | 55254741845582 |
10 | 14203544040353 |
11 | 4586764363858 |
12 | 17148aa1b1a55 |
13 | 7c050858c305 |
14 | 3716530d3853 |
15 | 19970057d688 |
hex | ceb053273a1 |
14203544040353 has 8 divisors (see below), whose sum is σ = 15040924074720. Its totient is φ = 13366372610880.
The previous prime is 14203544040349. The next prime is 14203544040379. The reversal of 14203544040353 is 35304044530241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14203544040353 - 22 = 14203544040349 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14203544040953) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52011023 + ... + 52283396.
It is an arithmetic number, because the mean of its divisors is an integer number (1880115509340).
Almost surely, 214203544040353 is an apocalyptic number.
It is an amenable number.
14203544040353 is a deficient number, since it is larger than the sum of its proper divisors (837380034367).
14203544040353 is a wasteful number, since it uses less digits than its factorization.
14203544040353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104302447.
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 14203544040353 its reverse (35304044530241), we get a palindrome (49507588570594).
The spelling of 14203544040353 in words is "fourteen trillion, two hundred three billion, five hundred forty-four million, forty thousand, three hundred fifty-three".
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