Base | Representation |
---|---|
bin | 11010011101001111… |
… | …11110011111011001 |
3 | 1100122220100011212211 |
4 | 31032213332133121 |
5 | 213042211114223 |
6 | 10305241035121 |
7 | 1011663021202 |
oct | 151647763731 |
9 | 40586304784 |
10 | 14204004313 |
11 | 6029876744 |
12 | 2904a85aa1 |
13 | 14549689a5 |
14 | 98a61c5a9 |
15 | 581ecdd0d |
hex | 34e9fe7d9 |
14204004313 has 2 divisors, whose sum is σ = 14204004314. Its totient is φ = 14204004312.
The previous prime is 14204004281. The next prime is 14204004319. The reversal of 14204004313 is 31340040241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10983668809 + 3220335504 = 104803^2 + 56748^2 .
It is an emirp because it is prime and its reverse (31340040241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14204004313 - 25 = 14204004281 is a prime.
It is not a weakly prime, because it can be changed into another prime (14204004319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102002156 + 7102002157.
It is an arithmetic number, because the mean of its divisors is an integer number (7102002157).
Almost surely, 214204004313 is an apocalyptic number.
It is an amenable number.
14204004313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14204004313 is an equidigital number, since it uses as much as digits as its factorization.
14204004313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14204004313 its reverse (31340040241), we get a palindrome (45544044554).
The spelling of 14204004313 in words is "fourteen billion, two hundred four million, four thousand, three hundred thirteen".
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