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142043124242321 is a prime number
BaseRepresentation
bin100000010010111111111101…
…111101101001011110010001
3200121221012010112221212211022
4200102333331331221132101
5122104213304301223241
61222033413242125225
741630164014561131
oct4022777575513621
9617835115855738
10142043124242321
114129417263a615
1213b20aaaab0815
1361347bc38c703
142710cd1252ac1
151164d033d754b
hex812ffdf69791

142043124242321 has 2 divisors, whose sum is σ = 142043124242322. Its totient is φ = 142043124242320.

The previous prime is 142043124242303. The next prime is 142043124242339. The reversal of 142043124242321 is 123242421340241.

It is a balanced prime because it is at equal distance from previous prime (142043124242303) and next prime (142043124242339).

It can be written as a sum of positive squares in only one way, i.e., 113727529104721 + 28315595137600 = 10664311^2 + 5321240^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142043124242321 is a prime.

It is not a weakly prime, because it can be changed into another prime (142043124242021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71021562121160 + 71021562121161.

It is an arithmetic number, because the mean of its divisors is an integer number (71021562121161).

Almost surely, 2142043124242321 is an apocalyptic number.

It is an amenable number.

142043124242321 is a deficient number, since it is larger than the sum of its proper divisors (1).

142043124242321 is an equidigital number, since it uses as much as digits as its factorization.

142043124242321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 142043124242321 its reverse (123242421340241), we get a palindrome (265285545582562).

The spelling of 142043124242321 in words is "one hundred forty-two trillion, forty-three billion, one hundred twenty-four million, two hundred forty-two thousand, three hundred twenty-one".