14204411114 has 4 divisors (see below), whose sum is σ = 21306616674. Its totient is φ = 7102205556.

The previous prime is 14204411107. The next prime is 14204411119. The reversal of 14204411114 is 41111440241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41111440241 = 164809 ⋅249449.

It can be written as a sum of positive squares in only one way, i.e., 10571335489 + 3633075625 = 102817^2 + 60275^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14204411114.

It is not an unprimeable number, because it can be changed into a prime (14204411119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3551102777 + ... + 3551102780.

Almost surely, 2^14204411114 is an apocalyptic number.

14204411114 is a deficient number, since it is larger than the sum of its proper divisors (7102205560).

14204411114 is an equidigital number, since it uses as much as digits as its factorization.

14204411114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7102205559.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 14204411114 its reverse (41111440241), we get a palindrome (55315851355).

The spelling of 14204411114 in words is "fourteen billion, two hundred four million, four hundred eleven thousand, one hundred fourteen".