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14204412141403 = 111291310194673
BaseRepresentation
bin1100111010110011100011…
…1100001001111101011011
31212021221001220102122102111
43032230320330021331123
53330211114002011103
650113230012413151
72664143401031431
oct316547074117533
955257056378374
1014204412141403
11458706a388a40
121714ab0a771b7
137c0616397583
143716d6508d51
151997518a886d
hexceb38f09f5b

14204412141403 has 4 divisors (see below), whose sum is σ = 15495722336088. Its totient is φ = 12913101946720.

The previous prime is 14204412141383. The next prime is 14204412141473. The reversal of 14204412141403 is 30414121440241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14204412141403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14204412141473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 645655097326 + ... + 645655097347.

It is an arithmetic number, because the mean of its divisors is an integer number (3873930584022).

Almost surely, 214204412141403 is an apocalyptic number.

14204412141403 is a deficient number, since it is larger than the sum of its proper divisors (1291310194685).

14204412141403 is a wasteful number, since it uses less digits than its factorization.

14204412141403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1291310194684.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 14204412141403 its reverse (30414121440241), we get a palindrome (44618533581644).

The spelling of 14204412141403 in words is "fourteen trillion, two hundred four billion, four hundred twelve million, one hundred forty-one thousand, four hundred three".

Divisors: 1 11 1291310194673 14204412141403