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14204422545233 is a prime number
BaseRepresentation
bin1100111010110011100110…
…0011110101111101010001
31212021221002122000012210112
43032230321203311331101
53330211124132421413
650113231023411105
72664143555332334
oct316547143657521
955257078005715
1014204422545233
114587075244548
121714ab4453a95
137c061859ab9b
143716d7a5661b
151997527612a8
hexceb398f5f51

14204422545233 has 2 divisors, whose sum is σ = 14204422545234. Its totient is φ = 14204422545232.

The previous prime is 14204422545223. The next prime is 14204422545253. The reversal of 14204422545233 is 33254522440241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13957158021184 + 247264524049 = 3735928^2 + 497257^2 .

It is an emirp because it is prime and its reverse (33254522440241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14204422545233 - 210 = 14204422544209 is a prime.

It is not a weakly prime, because it can be changed into another prime (14204422545223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102211272616 + 7102211272617.

It is an arithmetic number, because the mean of its divisors is an integer number (7102211272617).

Almost surely, 214204422545233 is an apocalyptic number.

It is an amenable number.

14204422545233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204422545233 is an equidigital number, since it uses as much as digits as its factorization.

14204422545233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 921600, while the sum is 41.

Adding to 14204422545233 its reverse (33254522440241), we get a palindrome (47458944985474).

The spelling of 14204422545233 in words is "fourteen trillion, two hundred four billion, four hundred twenty-two million, five hundred forty-five thousand, two hundred thirty-three".