Base | Representation |
---|---|
bin | 1100111010110011100110… |
… | …0011110101111101000111 |
3 | 1212021221002122000012210011 |
4 | 3032230321203311331013 |
5 | 3330211124132421343 |
6 | 50113231023411051 |
7 | 2664143555332321 |
oct | 316547143657507 |
9 | 55257078005704 |
10 | 14204422545223 |
11 | 4587075244539 |
12 | 1714ab4453a87 |
13 | 7c061859ab91 |
14 | 3716d7a56611 |
15 | 19975276129d |
hex | ceb398f5f47 |
14204422545223 has 2 divisors, whose sum is σ = 14204422545224. Its totient is φ = 14204422545222.
The previous prime is 14204422545197. The next prime is 14204422545233. The reversal of 14204422545223 is 32254522440241.
It is a strong prime.
It is an emirp because it is prime and its reverse (32254522440241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14204422545223 - 213 = 14204422537031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14204422545233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102211272611 + 7102211272612.
It is an arithmetic number, because the mean of its divisors is an integer number (7102211272612).
Almost surely, 214204422545223 is an apocalyptic number.
14204422545223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14204422545223 is an equidigital number, since it uses as much as digits as its factorization.
14204422545223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 614400, while the sum is 40.
Adding to 14204422545223 its reverse (32254522440241), we get a palindrome (46458944985464).
The spelling of 14204422545223 in words is "fourteen trillion, two hundred four billion, four hundred twenty-two million, five hundred forty-five thousand, two hundred twenty-three".
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