14204451113 has 4 divisors (see below), whose sum is σ = 14822035968. Its totient is φ = 13586866260.

The previous prime is 14204451109. The next prime is 14204451187. The reversal of 14204451113 is 31115440241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31115440241 = 547 ⋅56883803.

It is a cyclic number.

It is not a de Polignac number, because 14204451113 - 2² = 14204451109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14204454113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308792393 + ... + 308792438.

It is an arithmetic number, because the mean of its divisors is an integer number (3705508992).

Almost surely, 2^14204451113 is an apocalyptic number.

It is an amenable number.

14204451113 is a deficient number, since it is larger than the sum of its proper divisors (617584855).

14204451113 is an equidigital number, since it uses as much as digits as its factorization.

14204451113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617584854.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 14204451113 its reverse (31115440241), we get a palindrome (45319891354).

The spelling of 14204451113 in words is "fourteen billion, two hundred four million, four hundred fifty-one thousand, one hundred thirteen".