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1420466352541 is a prime number
BaseRepresentation
bin10100101010111010011…
…001000111000110011101
312000210110202001020010221
4110222322121013012131
5141233103341240131
63004315255401341
7204424323531235
oct24527231070635
95023422036127
101420466352541
114a8464251935
121ab367383251
13a3c45ab5652
144ca72808cc5
1526e39ce9411
hex14aba64719d

1420466352541 has 2 divisors, whose sum is σ = 1420466352542. Its totient is φ = 1420466352540.

The previous prime is 1420466352521. The next prime is 1420466352551. The reversal of 1420466352541 is 1452536640241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1419171864100 + 1294488441 = 1191290^2 + 35979^2 .

It is a cyclic number.

It is not a de Polignac number, because 1420466352541 - 27 = 1420466352413 is a prime.

It is a super-2 number, since 2×14204663525412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1420466352511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710233176270 + 710233176271.

It is an arithmetic number, because the mean of its divisors is an integer number (710233176271).

Almost surely, 21420466352541 is an apocalyptic number.

It is an amenable number.

1420466352541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420466352541 is an equidigital number, since it uses as much as digits as its factorization.

1420466352541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 1420466352541 in words is "one trillion, four hundred twenty billion, four hundred sixty-six million, three hundred fifty-two thousand, five hundred forty-one".