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14206734953 is a prime number
BaseRepresentation
bin11010011101100100…
…11001001001101001
31100200002110220121122
431032302121021221
5213043411004303
610305415345025
71012025153225
oct151662311151
940602426548
1014206734953
116030371274
122905982175
1314553b3858
1498ab2d785
1558236ce38
hex34ec99269

14206734953 has 2 divisors, whose sum is σ = 14206734954. Its totient is φ = 14206734952.

The previous prime is 14206734943. The next prime is 14206734961. The reversal of 14206734953 is 35943760241.

14206734953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11216504464 + 2990230489 = 105908^2 + 54683^2 .

It is an emirp because it is prime and its reverse (35943760241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14206734953 - 230 = 13132993129 is a prime.

It is not a weakly prime, because it can be changed into another prime (14206734943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7103367476 + 7103367477.

It is an arithmetic number, because the mean of its divisors is an integer number (7103367477).

Almost surely, 214206734953 is an apocalyptic number.

It is an amenable number.

14206734953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14206734953 is an equidigital number, since it uses as much as digits as its factorization.

14206734953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 44.

The spelling of 14206734953 in words is "fourteen billion, two hundred six million, seven hundred thirty-four thousand, nine hundred fifty-three".