Base | Representation |
---|---|
bin | 10100101011001011001… |
… | …101001000011111001111 |
3 | 12000211012101211000001020 |
4 | 110223023031020133033 |
5 | 141234143044101132 |
6 | 3004403253245223 |
7 | 204434320233351 |
oct | 24531315103717 |
9 | 5024171730036 |
10 | 1420748425167 |
11 | 4a85994a1205 |
12 | 1ab425933813 |
13 | a3c8c377526 |
14 | 4ca9c0730d1 |
15 | 26e5496652c |
hex | 14acb3487cf |
1420748425167 has 4 divisors (see below), whose sum is σ = 1894331233560. Its totient is φ = 947165616776.
The previous prime is 1420748425163. The next prime is 1420748425171. The reversal of 1420748425167 is 7615248470241.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1420748425163) and next prime (1420748425171).
It is a cyclic number.
It is not a de Polignac number, because 1420748425167 - 22 = 1420748425163 is a prime.
It is a super-2 number, since 2×14207484251672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420748425163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236791404192 + ... + 236791404197.
It is an arithmetic number, because the mean of its divisors is an integer number (473582808390).
Almost surely, 21420748425167 is an apocalyptic number.
1420748425167 is a deficient number, since it is larger than the sum of its proper divisors (473582808393).
1420748425167 is an equidigital number, since it uses as much as digits as its factorization.
1420748425167 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 473582808392.
The product of its (nonzero) digits is 3010560, while the sum is 51.
The spelling of 1420748425167 in words is "one trillion, four hundred twenty billion, seven hundred forty-eight million, four hundred twenty-five thousand, one hundred sixty-seven".
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