Base | Representation |
---|---|
bin | 10100101011011010011… |
… | …001011100101110011111 |
3 | 12000211212011102121002110 |
4 | 110223122121130232133 |
5 | 141240203321441111 |
6 | 3004444440325103 |
7 | 204443533600632 |
oct | 24533231345637 |
9 | 5024764377073 |
10 | 1421003312031 |
11 | 4a870a362506 |
12 | 1ab497173793 |
13 | a400010b364 |
14 | 4cac3c61c19 |
15 | 26e6c0135a6 |
hex | 14ada65cb9f |
1421003312031 has 32 divisors (see below), whose sum is σ = 1991860416000. Its totient is φ = 901080622464.
The previous prime is 1421003312017. The next prime is 1421003312087. The reversal of 1421003312031 is 1302133001241.
It is not a de Polignac number, because 1421003312031 - 223 = 1420994923423 is a prime.
It is a super-2 number, since 2×14210033120312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1421003311989 and 1421003312007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1421003312011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6424935 + ... + 6642423.
It is an arithmetic number, because the mean of its divisors is an integer number (62245638000).
Almost surely, 21421003312031 is an apocalyptic number.
1421003312031 is a deficient number, since it is larger than the sum of its proper divisors (570857103969).
1421003312031 is an equidigital number, since it uses as much as digits as its factorization.
1421003312031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 217740 (or 217694 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1421003312031 its reverse (1302133001241), we get a palindrome (2723136313272).
The spelling of 1421003312031 in words is "one trillion, four hundred twenty-one billion, three million, three hundred twelve thousand, thirty-one".
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