Base | Representation |
---|---|
bin | 1000010001010111011… |
… | …0100011101111110110 |
3 | 111120210020020121002201 |
4 | 2010111312203233312 |
5 | 4312010214411002 |
6 | 145140255455114 |
7 | 13160245461520 |
oct | 2042566435766 |
9 | 446706217081 |
10 | 142100544502 |
11 | 552a0064334 |
12 | 2365922749a |
13 | 10527b10937 |
14 | 6c405baa10 |
15 | 3a6a345087 |
hex | 2115da3bf6 |
142100544502 has 16 divisors (see below), whose sum is σ = 243732867840. Its totient is φ = 60867249768.
The previous prime is 142100544479. The next prime is 142100544541. The reversal of 142100544502 is 205445001241.
It is a super-3 number, since 3×1421005445023 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2721852 + ... + 2773567.
It is an arithmetic number, because the mean of its divisors is an integer number (15233304240).
Almost surely, 2142100544502 is an apocalyptic number.
142100544502 is a deficient number, since it is larger than the sum of its proper divisors (101632323338).
142100544502 is a wasteful number, since it uses less digits than its factorization.
142100544502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5497275.
The product of its (nonzero) digits is 6400, while the sum is 28.
Adding to 142100544502 its reverse (205445001241), we get a palindrome (347545545743).
The spelling of 142100544502 in words is "one hundred forty-two billion, one hundred million, five hundred forty-four thousand, five hundred two".
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