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14210155457 is a prime number
BaseRepresentation
bin11010011101111110…
…11100001111000001
31100200022220200122222
431032333130033001
5213100244433312
610310020540425
71012066220441
oct151677341701
940608820588
1014210155457
116032298133
122906b51715
131456010714
1498b380121
155827e6672
hex34efdc3c1

14210155457 has 2 divisors, whose sum is σ = 14210155458. Its totient is φ = 14210155456.

The previous prime is 14210155429. The next prime is 14210155459. The reversal of 14210155457 is 75455101241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11066198416 + 3143957041 = 105196^2 + 56071^2 .

It is a cyclic number.

It is not a de Polignac number, because 14210155457 - 216 = 14210089921 is a prime.

It is a super-2 number, since 2×142101554572 (a number of 21 digits) contains 22 as substring.

Together with 14210155459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14210155459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105077728 + 7105077729.

It is an arithmetic number, because the mean of its divisors is an integer number (7105077729).

Almost surely, 214210155457 is an apocalyptic number.

It is an amenable number.

14210155457 is a deficient number, since it is larger than the sum of its proper divisors (1).

14210155457 is an equidigital number, since it uses as much as digits as its factorization.

14210155457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28000, while the sum is 35.

Adding to 14210155457 its reverse (75455101241), we get a palindrome (89665256698).

The spelling of 14210155457 in words is "fourteen billion, two hundred ten million, one hundred fifty-five thousand, four hundred fifty-seven".