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14210223303 = 34736741101
BaseRepresentation
bin11010011101111111…
…01100110011000111
31100200100001010201210
431032333230303013
5213100304121203
610310022222503
71012066622313
oct151677546307
940610033653
1014210223303
116032334101
122906b84a33
131456035573
1498b39ab43
1558280b803
hex34efeccc7

14210223303 has 4 divisors (see below), whose sum is σ = 18946964408. Its totient is φ = 9473482200.

The previous prime is 14210223257. The next prime is 14210223311. The reversal of 14210223303 is 30332201241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14210223303 - 225 = 14176668871 is a prime.

It is a super-2 number, since 2×142102233032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14210223303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14210223383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368370548 + ... + 2368370553.

It is an arithmetic number, because the mean of its divisors is an integer number (4736741102).

Almost surely, 214210223303 is an apocalyptic number.

14210223303 is a deficient number, since it is larger than the sum of its proper divisors (4736741105).

14210223303 is an equidigital number, since it uses as much as digits as its factorization.

14210223303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4736741104.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 14210223303 its reverse (30332201241), we get a palindrome (44542424544).

The spelling of 14210223303 in words is "fourteen billion, two hundred ten million, two hundred twenty-three thousand, three hundred three".

Divisors: 1 3 4736741101 14210223303