Base | Representation |
---|---|
bin | 11010011110000000… |
… | …01010011000000011 |
3 | 1100200100021021220202 |
4 | 31033000022120003 |
5 | 213100322010301 |
6 | 10310024555415 |
7 | 1012100635442 |
oct | 151700123003 |
9 | 40610237822 |
10 | 14210344451 |
11 | 6032407126 |
12 | 2907022b6b |
13 | 1456078754 |
14 | 98b3ccd59 |
15 | 58283266b |
hex | 34f00a603 |
14210344451 has 2 divisors, whose sum is σ = 14210344452. Its totient is φ = 14210344450.
The previous prime is 14210344439. The next prime is 14210344457. The reversal of 14210344451 is 15444301241.
It is a strong prime.
It is an emirp because it is prime and its reverse (15444301241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14210344451 - 218 = 14210082307 is a prime.
It is not a weakly prime, because it can be changed into another prime (14210344457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105172225 + 7105172226.
It is an arithmetic number, because the mean of its divisors is an integer number (7105172226).
Almost surely, 214210344451 is an apocalyptic number.
14210344451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14210344451 is an equidigital number, since it uses as much as digits as its factorization.
14210344451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 14210344451 its reverse (15444301241), we get a palindrome (29654645692).
The spelling of 14210344451 in words is "fourteen billion, two hundred ten million, three hundred forty-four thousand, four hundred fifty-one".
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