Base | Representation |
---|---|
bin | 10100101011011100010… |
… | …011010000001010010011 |
3 | 12000211221101111210221202 |
4 | 110223130103100022103 |
5 | 141240240010222011 |
6 | 3004451540541415 |
7 | 204444402155411 |
oct | 24533423201223 |
9 | 5024841453852 |
10 | 1421035242131 |
11 | 4a872639101a |
12 | 1ab4a59b186b |
13 | a400690a9cb |
14 | 4cac81b42b1 |
15 | 26e6ec1e23b |
hex | 14adc4d0293 |
1421035242131 has 4 divisors (see below), whose sum is σ = 1421320195032. Its totient is φ = 1420750289232.
The previous prime is 1421035242101. The next prime is 1421035242181. The reversal of 1421035242131 is 1312425301241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1421035242131 - 210 = 1421035241107 is a prime.
It is a super-2 number, since 2×14210352421312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1421035242094 and 1421035242103.
It is not an unprimeable number, because it can be changed into a prime (1421035242101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142468970 + ... + 142478943.
It is an arithmetic number, because the mean of its divisors is an integer number (355330048758).
Almost surely, 21421035242131 is an apocalyptic number.
1421035242131 is a deficient number, since it is larger than the sum of its proper divisors (284952901).
1421035242131 is an equidigital number, since it uses as much as digits as its factorization.
1421035242131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284952900.
The product of its (nonzero) digits is 5760, while the sum is 29.
The spelling of 1421035242131 in words is "one trillion, four hundred twenty-one billion, thirty-five million, two hundred forty-two thousand, one hundred thirty-one".
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