Base | Representation |
---|---|
bin | 100000010011111000110001… |
… | …101111100111111111001111 |
3 | 200122011000120121222122001012 |
4 | 200103320301233213333033 |
5 | 122111213220331223344 |
6 | 1222121422131035435 |
7 | 41634453425450645 |
oct | 4023706157477717 |
9 | 618130517878035 |
10 | 142104122523599 |
11 | 41308024577125 |
12 | 13b3089313bb7b |
13 | 613a4908a4682 |
14 | 2713c3a527195 |
15 | 11666c35cc29e |
hex | 813e31be7fcf |
142104122523599 has 2 divisors, whose sum is σ = 142104122523600. Its totient is φ = 142104122523598.
The previous prime is 142104122523551. The next prime is 142104122523611. The reversal of 142104122523599 is 995325221401241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142104122523599 - 240 = 141004610895823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142104122523899) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71052061261799 + 71052061261800.
It is an arithmetic number, because the mean of its divisors is an integer number (71052061261800).
Almost surely, 2142104122523599 is an apocalyptic number.
142104122523599 is a deficient number, since it is larger than the sum of its proper divisors (1).
142104122523599 is an equidigital number, since it uses as much as digits as its factorization.
142104122523599 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1555200, while the sum is 50.
The spelling of 142104122523599 in words is "one hundred forty-two trillion, one hundred four billion, one hundred twenty-two million, five hundred twenty-three thousand, five hundred ninety-nine".
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