142111031240131 has 2 divisors, whose sum is σ = 142111031240132. Its totient is φ = 142111031240130.

The previous prime is 142111031240111. The next prime is 142111031240219. The reversal of 142111031240131 is 131042130111241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142111031240131 - 2⁵ = 142111031240099 is a prime.

It is a super-2 number, since 2×142111031240131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142111031240096 and 142111031240105.

It is not a weakly prime, because it can be changed into another prime (142111031240111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71055515620065 + 71055515620066.

It is an arithmetic number, because the mean of its divisors is an integer number (71055515620066).

Almost surely, 2^{142111031240131} is an apocalyptic number.

142111031240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

142111031240131 is an equidigital number, since it uses as much as digits as its factorization.

142111031240131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 142111031240131 its reverse (131042130111241), we get a palindrome (273153161351372).

The spelling of 142111031240131 in words is "one hundred forty-two trillion, one hundred eleven billion, thirty-one million, two hundred forty thousand, one hundred thirty-one".