Search a number
-
+
1421111103 = 3473703701
BaseRepresentation
bin101010010110100…
…0110111100111111
310200001001220221120
41110231012330333
510402301023403
6353003202023
750134150026
oct12455067477
93601056846
101421111103
1166a1a8895
12337b16313
13198560859
14d6a498bd
1584b64e53
hex54b46f3f

1421111103 has 4 divisors (see below), whose sum is σ = 1894814808. Its totient is φ = 947407400.

The previous prime is 1421111063. The next prime is 1421111113. The reversal of 1421111103 is 3011111241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421111103 - 213 = 1421102911 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421111113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236851848 + ... + 236851853.

It is an arithmetic number, because the mean of its divisors is an integer number (473703702).

Almost surely, 21421111103 is an apocalyptic number.

1421111103 is a deficient number, since it is larger than the sum of its proper divisors (473703705).

1421111103 is an equidigital number, since it uses as much as digits as its factorization.

1421111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 473703704.

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 1421111103 is about 37697.6272860773. The cubic root of 1421111103 is about 1124.2839500673.

Adding to 1421111103 its reverse (3011111241), we get a palindrome (4432222344).

The spelling of 1421111103 in words is "one billion, four hundred twenty-one million, one hundred eleven thousand, one hundred three".

Divisors: 1 3 473703701 1421111103