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1421121412101 = 3473707137367
BaseRepresentation
bin10100101011100001011…
…011111101110000000101
312000212011101122200221010
4110223201123331300011
5141240424040141401
63004504255512433
7204446466456666
oct24534133756005
95025141580833
101421121412101
114a876aa96876
121ab50a828719
13a401b71b561
144cad580536d
1526e77590ed6
hex14ae16fdc05

1421121412101 has 4 divisors (see below), whose sum is σ = 1894828549472. Its totient is φ = 947414274732.

The previous prime is 1421121412099. The next prime is 1421121412121. The reversal of 1421121412101 is 1012141211241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1421121412101 - 21 = 1421121412099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1421121412121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236853568681 + ... + 236853568686.

It is an arithmetic number, because the mean of its divisors is an integer number (473707137368).

Almost surely, 21421121412101 is an apocalyptic number.

It is an amenable number.

1421121412101 is a deficient number, since it is larger than the sum of its proper divisors (473707137371).

1421121412101 is an equidigital number, since it uses as much as digits as its factorization.

1421121412101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 473707137370.

The product of its (nonzero) digits is 128, while the sum is 21.

Adding to 1421121412101 its reverse (1012141211241), we get a palindrome (2433262623342).

The spelling of 1421121412101 in words is "one trillion, four hundred twenty-one billion, one hundred twenty-one million, four hundred twelve thousand, one hundred one".

Divisors: 1 3 473707137367 1421121412101