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14211230433033 = 34737076811011
BaseRepresentation
bin1100111011001100111101…
…0101110111111100001001
31212022120200002020202012010
43032303033111313330021
53330314044442324113
650120314340210133
72664504352405614
oct316631725677411
955276602222163
1014211230433033
114589a491033a7
121716294399949
137c1161b4bb6a
14371b81c8517b
15199a0027d1c3
hexceccf577f09

14211230433033 has 4 divisors (see below), whose sum is σ = 18948307244048. Its totient is φ = 9474153622020.

The previous prime is 14211230433031. The next prime is 14211230433079. The reversal of 14211230433033 is 33033403211241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14211230433033 - 21 = 14211230433031 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14211230433031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368538405503 + ... + 2368538405508.

It is an arithmetic number, because the mean of its divisors is an integer number (4737076811012).

Almost surely, 214211230433033 is an apocalyptic number.

It is an amenable number.

14211230433033 is a deficient number, since it is larger than the sum of its proper divisors (4737076811015).

14211230433033 is an equidigital number, since it uses as much as digits as its factorization.

14211230433033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4737076811014.

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 14211230433033 its reverse (33033403211241), we get a palindrome (47244633644274).

The spelling of 14211230433033 in words is "fourteen trillion, two hundred eleven billion, two hundred thirty million, four hundred thirty-three thousand, thirty-three".

Divisors: 1 3 4737076811011 14211230433033