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1421124339433 is a prime number
BaseRepresentation
bin10100101011100001100…
…111001000011011101001
312000212011121011102110211
4110223201213020123221
5141240430312330213
63004504442341121
7204446533401331
oct24534147103351
95025147142424
101421124339433
114a8771706157
121ab50b7ba7a1
13a401c204ac6
144cad5d680c1
1526e7796d53d
hex14ae19c86e9

1421124339433 has 2 divisors, whose sum is σ = 1421124339434. Its totient is φ = 1421124339432.

The previous prime is 1421124339413. The next prime is 1421124339463. The reversal of 1421124339433 is 3349334211241.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1045982789289 + 375141550144 = 1022733^2 + 612488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1421124339433 is a prime.

It is a super-2 number, since 2×14211243394332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1421124339413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710562169716 + 710562169717.

It is an arithmetic number, because the mean of its divisors is an integer number (710562169717).

Almost surely, 21421124339433 is an apocalyptic number.

It is an amenable number.

1421124339433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421124339433 is an equidigital number, since it uses as much as digits as its factorization.

1421124339433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 186624, while the sum is 40.

The spelling of 1421124339433 in words is "one trillion, four hundred twenty-one billion, one hundred twenty-four million, three hundred thirty-nine thousand, four hundred thirty-three".