142113110133 has 4 divisors (see below), whose sum is σ = 189484146848. Its totient is φ = 94742073420.

The previous prime is 142113110131. The next prime is 142113110141. The reversal of 142113110133 is 331011311241.

142113110133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 142113110133 - 2¹ = 142113110131 is a prime.

It is a super-2 number, since 2×142113110133² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142113110131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23685518353 + ... + 23685518358.

It is an arithmetic number, because the mean of its divisors is an integer number (47371036712).

Almost surely, 2^142113110133 is an apocalyptic number.

It is an amenable number.

142113110133 is a deficient number, since it is larger than the sum of its proper divisors (47371036715).

142113110133 is an equidigital number, since it uses as much as digits as its factorization.

142113110133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47371036714.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 142113110133 its reverse (331011311241), we get a palindrome (473124421374).

The spelling of 142113110133 in words is "one hundred forty-two billion, one hundred thirteen million, one hundred ten thousand, one hundred thirty-three".