Base | Representation |
---|---|
bin | 1000010001011100010… |
… | …0111111010000100111 |
3 | 111120211122221011000021 |
4 | 2010113010333100213 |
5 | 4312031000320143 |
6 | 145142312300011 |
7 | 13160615312134 |
oct | 2042704772047 |
9 | 446748834007 |
10 | 142121104423 |
11 | 55300727301 |
12 | 236640a1607 |
13 | 1052c15bb7c |
14 | 6c4320d58b |
15 | 3a6c056ced |
hex | 211713f427 |
142121104423 has 2 divisors, whose sum is σ = 142121104424. Its totient is φ = 142121104422.
The previous prime is 142121104403. The next prime is 142121104459. The reversal of 142121104423 is 324401121241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142121104423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142121104403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71060552211 + 71060552212.
It is an arithmetic number, because the mean of its divisors is an integer number (71060552212).
Almost surely, 2142121104423 is an apocalyptic number.
142121104423 is a deficient number, since it is larger than the sum of its proper divisors (1).
142121104423 is an equidigital number, since it uses as much as digits as its factorization.
142121104423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 142121104423 its reverse (324401121241), we get a palindrome (466522225664).
The spelling of 142121104423 in words is "one hundred forty-two billion, one hundred twenty-one million, one hundred four thousand, four hundred twenty-three".
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