14212113 has 4 divisors (see below), whose sum is σ = 18949488. Its totient is φ = 9474740.

The previous prime is 14212103. The next prime is 14212127. The reversal of 14212113 is 31121241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14212113 - 2⁶ = 14212049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14212092 and 14212101.

It is not an unprimeable number, because it can be changed into a prime (14212103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368683 + ... + 2368688.

It is an arithmetic number, because the mean of its divisors is an integer number (4737372).

Almost surely, 2^14212113 is an apocalyptic number.

It is an amenable number.

14212113 is a deficient number, since it is larger than the sum of its proper divisors (4737375).

14212113 is an equidigital number, since it uses as much as digits as its factorization.

14212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4737374.

The product of its digits is 48, while the sum is 15.

The square root of 14212113 is about 3769.8956218972. The cubic root of 14212113 is about 242.2253268672.

Adding to 14212113 its reverse (31121241), we get a palindrome (45333354).

The spelling of 14212113 in words is "fourteen million, two hundred twelve thousand, one hundred thirteen".