Base | Representation |
---|---|
bin | 1100111011010000100100… |
… | …1001110010010111111111 |
3 | 1212022200011200022021120221 |
4 | 3032310021021302113333 |
5 | 3330323041241434124 |
6 | 50120554504522211 |
7 | 2664540400454566 |
oct | 316641111622777 |
9 | 55280150267527 |
10 | 14212200343039 |
11 | 458a3a6645116 |
12 | 1716505180367 |
13 | 7c1287a820ca |
14 | 371c349dcbdd |
15 | 199a5a4b8ce4 |
hex | ced092725ff |
14212200343039 has 4 divisors (see below), whose sum is σ = 14212705012056. Its totient is φ = 14211695674024.
The previous prime is 14212200342979. The next prime is 14212200343111. The reversal of 14212200343039 is 93034300221241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14212200343039 - 27 = 14212200342911 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14212200342995 and 14212200343013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14212200343139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252292264 + ... + 252348589.
It is an arithmetic number, because the mean of its divisors is an integer number (3553176253014).
Almost surely, 214212200343039 is an apocalyptic number.
14212200343039 is a deficient number, since it is larger than the sum of its proper divisors (504669017).
14212200343039 is an equidigital number, since it uses as much as digits as its factorization.
14212200343039 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 504669016.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 14212200343039 in words is "fourteen trillion, two hundred twelve billion, two hundred million, three hundred forty-three thousand, thirty-nine".
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