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14212250051 is a prime number
BaseRepresentation
bin11010011110001110…
…11011100111000011
31100200110212002220112
431033013123213003
5213101314000201
610310133501535
71012123063226
oct151707334703
940613762815
1014212250051
1160334988aa
1229077a18ab
131456594c1c
1498b7675bd
15582aac0bb
hex34f1db9c3

14212250051 has 2 divisors, whose sum is σ = 14212250052. Its totient is φ = 14212250050.

The previous prime is 14212249991. The next prime is 14212250093. The reversal of 14212250051 is 15005221241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14212250051 - 210 = 14212249027 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 14212249999 and 14212250026.

It is not a weakly prime, because it can be changed into another prime (14212250251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106125025 + 7106125026.

It is an arithmetic number, because the mean of its divisors is an integer number (7106125026).

Almost surely, 214212250051 is an apocalyptic number.

14212250051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212250051 is an equidigital number, since it uses as much as digits as its factorization.

14212250051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 800, while the sum is 23.

Adding to 14212250051 its reverse (15005221241), we get a palindrome (29217471292).

The spelling of 14212250051 in words is "fourteen billion, two hundred twelve million, two hundred fifty thousand, fifty-one".