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142122663353 = 1112920242123
BaseRepresentation
bin1000010001011100101…
…0111011110110111001
3111120211202212100110102
42010113022323312321
54312031400211403
6145142405525145
713160634464126
oct2042712736671
9446752770412
10142122663353
11553015a1580
12236647137b5
131052c586608
146c434d774d
153a6c263b88
hex21172bbdb9

142122663353 has 4 divisors (see below), whose sum is σ = 155042905488. Its totient is φ = 129202421220.

The previous prime is 142122663323. The next prime is 142122663367. The reversal of 142122663353 is 353366221241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142122663353 - 234 = 124942794169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142122663323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6460121051 + ... + 6460121072.

It is an arithmetic number, because the mean of its divisors is an integer number (38760726372).

Almost surely, 2142122663353 is an apocalyptic number.

It is an amenable number.

142122663353 is a deficient number, since it is larger than the sum of its proper divisors (12920242135).

142122663353 is a wasteful number, since it uses less digits than its factorization.

142122663353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12920242134.

The product of its digits is 155520, while the sum is 38.

Adding to 142122663353 its reverse (353366221241), we get a palindrome (495488884594).

The spelling of 142122663353 in words is "one hundred forty-two billion, one hundred twenty-two million, six hundred sixty-three thousand, three hundred fifty-three".

Divisors: 1 11 12920242123 142122663353