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14212311313 is a prime number
BaseRepresentation
bin11010011110001111…
…01010100100010001
31100200110222012221111
431033013222210101
5213101322430223
610310135053321
71012123436644
oct151707524421
940613865844
1014212311313
11603352a932
122907811241
1314565b6a85
1498b781a5b
15582ac030d
hex34f1ea911

14212311313 has 2 divisors, whose sum is σ = 14212311314. Its totient is φ = 14212311312.

The previous prime is 14212311307. The next prime is 14212311343. The reversal of 14212311313 is 31311321241.

14212311313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8887398529 + 5324912784 = 94273^2 + 72972^2 .

It is an emirp because it is prime and its reverse (31311321241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14212311313 is a prime.

It is not a weakly prime, because it can be changed into another prime (14212311343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106155656 + 7106155657.

It is an arithmetic number, because the mean of its divisors is an integer number (7106155657).

Almost surely, 214212311313 is an apocalyptic number.

It is an amenable number.

14212311313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212311313 is an equidigital number, since it uses as much as digits as its factorization.

14212311313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 22.

Adding to 14212311313 its reverse (31311321241), we get a palindrome (45523632554).

The spelling of 14212311313 in words is "fourteen billion, two hundred twelve million, three hundred eleven thousand, three hundred thirteen".