Base | Representation |
---|---|
bin | 11010011110001111… |
… | …10001110110001011 |
3 | 1100200111000201211212 |
4 | 31033013301312023 |
5 | 213101324404011 |
6 | 10310135443335 |
7 | 1012123622612 |
oct | 151707616613 |
9 | 40614021755 |
10 | 14212341131 |
11 | 603355027a |
12 | 290782654b |
13 | 14565c7511 |
14 | 98b78c879 |
15 | 582ac908b |
hex | 34f1f1d8b |
14212341131 has 2 divisors, whose sum is σ = 14212341132. Its totient is φ = 14212341130.
The previous prime is 14212341119. The next prime is 14212341179. The reversal of 14212341131 is 13114321241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14212341131 - 26 = 14212341067 is a prime.
It is a super-2 number, since 2×142123411312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14212341097 and 14212341106.
It is not a weakly prime, because it can be changed into another prime (14212341191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106170565 + 7106170566.
It is an arithmetic number, because the mean of its divisors is an integer number (7106170566).
Almost surely, 214212341131 is an apocalyptic number.
14212341131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212341131 is an equidigital number, since it uses as much as digits as its factorization.
14212341131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
Adding to 14212341131 its reverse (13114321241), we get a palindrome (27326662372).
The spelling of 14212341131 in words is "fourteen billion, two hundred twelve million, three hundred forty-one thousand, one hundred thirty-one".
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