14212402344433 has 2 divisors, whose sum is σ = 14212402344434. Its totient is φ = 14212402344432.

The previous prime is 14212402344407. The next prime is 14212402344479. The reversal of 14212402344433 is 33444320421241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13211065898209 + 1001336446224 = 3634703^2 + 1000668^2 .

It is a cyclic number.

It is not a de Polignac number, because 14212402344433 - 2⁴¹ = 12013379088881 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14212402344392 and 14212402344401.

It is not a weakly prime, because it can be changed into another prime (14212402344493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106201172216 + 7106201172217.

It is an arithmetic number, because the mean of its divisors is an integer number (7106201172217).

Almost surely, 2^{14212402344433} is an apocalyptic number.

It is an amenable number.

14212402344433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212402344433 is an equidigital number, since it uses as much as digits as its factorization.

14212402344433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 14212402344433 its reverse (33444320421241), we get a palindrome (47656722765674).

It can be divided in two parts, 1421240 and 2344433, that added together give a palindrome (3765673).

The spelling of 14212402344433 in words is "fourteen trillion, two hundred twelve billion, four hundred two million, three hundred forty-four thousand, four hundred thirty-three".