Base | Representation |
---|---|
bin | 1100111011010001010101… |
… | …0011000100010010011101 |
3 | 1212022200200212201022202021 |
4 | 3032310111103010102131 |
5 | 3330324000422233201 |
6 | 50121031024100141 |
7 | 2664545423420116 |
oct | 316642523042235 |
9 | 55280625638667 |
10 | 14212404102301 |
11 | 458a4a06654a9 |
12 | 1716561464651 |
13 | 7c12bb054512 |
14 | 371c53abd20d |
15 | 199a6d316ea1 |
hex | ced154c449d |
14212404102301 has 2 divisors, whose sum is σ = 14212404102302. Its totient is φ = 14212404102300.
The previous prime is 14212404102287. The next prime is 14212404102307. The reversal of 14212404102301 is 10320140421241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12224106697401 + 1988297404900 = 3496299^2 + 1410070^2 .
It is a cyclic number.
It is not a de Polignac number, because 14212404102301 - 219 = 14212403578013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14212404102307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106202051150 + 7106202051151.
It is an arithmetic number, because the mean of its divisors is an integer number (7106202051151).
Almost surely, 214212404102301 is an apocalyptic number.
It is an amenable number.
14212404102301 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212404102301 is an equidigital number, since it uses as much as digits as its factorization.
14212404102301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14212404102301 its reverse (10320140421241), we get a palindrome (24532544523542).
The spelling of 14212404102301 in words is "fourteen trillion, two hundred twelve billion, four hundred four million, one hundred two thousand, three hundred one".
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