Base | Representation |
---|---|
bin | 1100111011010001010111… |
… | …1001010000010101010110 |
3 | 1212022200201120112220222222 |
4 | 3032310111321100111112 |
5 | 3330324011003104420 |
6 | 50121032022422342 |
7 | 2664545604463133 |
oct | 316642571202526 |
9 | 55280646486888 |
10 | 14212414113110 |
11 | 458a4a62827a4 |
12 | 17165648919b2 |
13 | 7c12c014ac85 |
14 | 371c5516758a |
15 | 199a6e143225 |
hex | ced15e50556 |
14212414113110 has 32 divisors (see below), whose sum is σ = 25713558313632. Its totient is φ = 5655861780480.
The previous prime is 14212414113083. The next prime is 14212414113187. The reversal of 14212414113110 is 1131141421241.
14212414113110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a self number, because there is not a number n which added to its sum of digits gives 14212414113110.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1325177 + ... + 5493716.
It is an arithmetic number, because the mean of its divisors is an integer number (803548697301).
Almost surely, 214212414113110 is an apocalyptic number.
14212414113110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14212414113110 is a deficient number, since it is larger than the sum of its proper divisors (11501144200522).
14212414113110 is a wasteful number, since it uses less digits than its factorization.
14212414113110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6819968.
The product of its (nonzero) digits is 768, while the sum is 26.
Adding to 14212414113110 its reverse (1131141421241), we get a palindrome (15343555534351).
The spelling of 14212414113110 in words is "fourteen trillion, two hundred twelve billion, four hundred fourteen million, one hundred thirteen thousand, one hundred ten".
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